If you write m = re.match(BanglaWordPattern, w) print m.group(0) you'll see that what actually matched was the empty string. You are not actually looking at the result of your program to see what it actually matched. The empty regular expression matches anything, of course. So there are really five alternatives, the last one being empty. That means the whole regular expression looks like (stuff1|stuff2|stuff3|stuff4|)+.

In the BanglaWordPattern regular expression, there is a vertical bar | near the end, with nothing after it. You just get backslashes, letters, and digits. This means that Unicode escape sequences like ক are not being translated into Unicode characters. Your strings in the BanglaAlphabet dictionary are lacking the u (Unicode) flag. Looking at the Bengali code chart it seems possible that you missed some other characters. U+09BC BENGALI SIGN NUKTA is not matched by your regular expression. Your string কয়া is made up of these characters: > import unicodedata Many ''.format(**bangla_alphabet), re.VERBOSE) I will be looking into those and adding them to this basic structure incrementally. There are several special rules / exceptions not implemented. As such, this code now serves as a very basic regular expression for validating the syntax of Bengali words.

I am happy to report that it is working as expected. This code not only corrects errors, but accounts for more characters and valid constructs than before. The matching is now: bangla_word_pattern.match(w) However, it is matching invalid words, such as োগাড় and িদগ.Īfter numerous corrections as suggested by and I ended up with: bangla_alphabet = dict(Ĭonsonant = u'',ĭependent_vowel = u'',ĭependent_sign = u'',īangla_word_pattern = re.compile(ur'''(?: This is meant to match a valid Bengali word when matched from right to left. The matching is done with: re.match(BanglaWordPattern, w) 'DependantVowel' : '',īanglaWordPattern = re.compile(BanglaWordPattern, re.VERBOSE)

Bengali alphabet consonant all